If X is an infinite set with the discrete topology, which subsets of X are compact ?
Give an example of a subspace of a metric space which is closed and bounded but not compact.
If A is a subset of R with its usual topology on which every continuous real-valued function is bounded, prove that A is compact.
Consider the real line R with the topology generated by sets of the form (r, ) for rR. Prove that this last result fails.
Define a metric on R by d(x, y) = |x - y| /(1 + |x - y|). Show that this metric is equivalent to the usual metric (i.e. the open sets are the same).
Show that in this metric there are closed bounded subsets which are not compact. Why does this not contradict the Heine-Borel theorem ?
Prove that if A and B are compact subspaces of a Hausdorff space then AB is compact.
(In fact the Hausdorff condition is necessary though it's a bit tricky to find an example to prove it.)
If A and B are compact is AB necessarily compact ?
If A and B are subspaces of a metric space define d(A, B) to be the greatest lower bound of the set {d(a, b) | aA, bB}. If A and B are compact prove that d(A, B) = d(p, q) for some pA, qB.
Show that if either A or B is non-compact this result may fail.